Comments for DivNull Productions

Comment on Looking for instructions for building Mobile Frame Zero frames? by Darrin Smith

Darrin Smith — Sun, 24 Mar 2013 18:05:49 +0000

Love the idea. Raiding my son’s box o’ bricks but I am not quite sure what to look for. With instructions I could use him to build me an army!

Comment on ’inkadia by Game Chef Review #2 – 'inkaida by Lester Ward » Geeky & Genki

Game Chef Review #2 – 'inkaida by Lester Ward » Geeky & Genki — Fri, 09 Nov 2012 16:11:06 +0000

[...] going for it: it’s unique. I’d love to see the result of other group’s efforts, and Ward has set up a space to display such efforts online. I’ll probably be bookmarking that on the off-chance anyone [...]

Comment on 3d6 probability graphic by Wordman

Wordman — Fri, 02 Nov 2012 02:50:59 +0000

The duplicates ABSOLUTELY DO matter to the probability of the outcomes, even if they don't matter to the result. For example, say your 3d6 are different colors, one red die, one blue die, one green die. Lets say you roll these and they add up to 17. You are right that any game you play wont really care which color die came up which; only the resulting sum matters to the outcome in the game. However, this chart isn't representing possible outcomes. It is representing the probability of those outcomes. And, to calculate that, it really does matter which color comes up which. Take a look at your table. It lists one result summing to 18 (i.e. all dice come up six), and one result summing to 17 (i.e. two dice come up six, one comes up five). Does this mean that rolling a 17 and an 18 are equally likely? Of course not. You can only get an 18 one way: the red die is six, the blue die is six and the green die is six. You can list this result as a (red, green, blue) triplet: (6,6,6). On the other hand you can get a 17 three distinct ways: (6,6,5), (5,6,6) or (6,5,6). In other words, you are three times more likely to get a 17 than an 18 on a 3d6. To figure out the probability, you have to count the distinct combinations, not just the results. Still don't believe me? Then lets play this game. We start rolling 3d6 over and over. Any time a 17 comes up, you pay me a dollar. Any time an 18 comes up, I pay you two dollars. If your result chart really is an accurate representation of the probability, then you can't lose. Since your chart says that 18 and 17 are equally likely, you should earn twice as much money as you pay, assuming we track a decent sample of rolls (say 1000 of them). I, on the other hand, will play this game with you any time you like, because I know that my probability chart correctly illustrates the chances of rolling a number on a 3d6. Since 17 will happen three times more often than 18, for every two dollars you earn, you will pay me three, on average. You can verify this by just rolling the dice 100 or 1000 times (or having a computer do it for you) and track the results.

Comment on 3d6 probability graphic by adam

adam — Sat, 13 Oct 2012 04:49:51 +0000

…and yes, my table DOES indicate the probability of result just as much as the length of a bar. just look at the length of the line. i’m sorry if you need a “pretty picture” to see it.

Comment on 3d6 probability graphic by adam

adam — Sat, 13 Oct 2012 04:44:22 +0000

table/bar graph, tom-A-to/tom-ah-to, whatever…

the duplicates DO NOT matter if you are throwing 3 die at one time. if i roll a 6, 5, and 4, it does not matter which die was the 6 or which die was the 5 or which die was the 4.

Comment on Three-Dragon Ante double-deck box by Mike

Mike — Thu, 27 Sep 2012 15:24:28 +0000

This is absolutely gorgeous! Any chance I could get the dimensions on the box you used?

Comment on My favorite review of ’inkadia by lucek

lucek — Mon, 06 Aug 2012 18:26:30 +0000

I had pretty the same feelings.

Comment on ’inkadia by My favorite review of ’inkadia | DivNull Productions

My favorite review of ’inkadia | DivNull Productions — Sat, 04 Aug 2012 00:42:38 +0000

[...] said this about ’inkadia: The Good: *stares at the work in shock, jaw on the floor* This is art imitating [...]

Comment on 3d6 probability graphic by wordman

wordman — Fri, 03 Aug 2012 15:21:45 +0000

Duplicates are shown because they matter to the probability a lot. The “table” as you call it isn’t a table of results: it is a bar graph. The length of the bar indicates how many combinations produce that result (i.e. the probability of that result). Your revised table doesn’t do that at all.

You are correct about the mistakes. The entry in 12 should, of course, be 4,3,5 and the one for 9 should be 4,1,4. I’ll correct this when I get a moment.

Comment on 3d6 probability graphic by adam

adam — Sun, 29 Jul 2012 20:08:01 +0000

why are ‘duplicates’ shown? in the context of RPGs (or really any context i can think of) you don’t care which die rolled what. you only care about the total of the dice.

as such, here is the revised table in text form:
18 = (6,6,6)
17 = (6,6,5)
16 = (6,6,4),(6,5,5)
15 = (6,6,3),(6,5,4),(5,5,5)
14 = (6,6,2),(6,5,3),(6,4,4),(5,5,4)
13 = (6,6,1),(6,5,2),(6,4,3),(5,5,3),(5,4,4)
12 = (6,5,1),(6,4,2),(6,3,3),(5,5,2),(5,4,3)
11 = (6,4,1),(6,3,2),(5,5,1),(5,4,2),(5,3,3),(4,4,3)
10 = (6,3,1),(6,2,2),(5,4,1),(5,3,2),(4,4.2),(4,3,3)
09 = (6,2,1),(5,3,1),(5,2,2),(4,4,1),(4,3,2)
08 = (6,1,1),(5,2,1),(4,3,1),(4,2,2),(3,3,2)
07 = (5,1,1),(4,2,1),(3,3,1),(3,2,2)
06 = (4,1,1),(3,2,1),(2,2,2)
05 = (3,1,1),(2,2,1)
04 = (2,1,1)
03 = (1,1,1)

*also note that 12 and 9 in the graphic chart have entries that are absolutely incorrect:
12 = (4,3,6) and 9 = (4,1,3)
i wasn’t really looking for those inaccuracies. there could be others.